{"id":759,"date":"2021-01-19T16:20:22","date_gmt":"2021-01-19T14:20:22","guid":{"rendered":"https:\/\/www.pealfa.duckdns.org\/wordpress\/?p=759"},"modified":"2021-01-19T17:23:36","modified_gmt":"2021-01-19T15:23:36","slug":"area-entre-dos-parabolas-con-un-parametro","status":"publish","type":"post","link":"https:\/\/www.pealfa.duckdns.org\/wordpress\/?p=759","title":{"rendered":"\u00c1rea entre dos par\u00e1bolas con un par\u00e1metro"},"content":{"rendered":"<p><script type=\"text\/javascript\">function SINO(cual) {\n   var elElemento=document.getElementById(cual);\n   if(elElemento.style.display == 'block') {\n      elElemento.style.display = 'none';\n   } else {\n      elElemento.style.display = 'block';\n   }\n}\n<\/script><\/p>\n<p>Hola. Una nueva entrada para el estudio del \u00e1rea del rencinto delimitado por dos curvas continuas.<\/p>\n<p>Pero hoy con una variaci\u00f3n: una de las curvas tiene un coeficiente literal (un par\u00e1metro). \u00bfQu\u00e9 valor del par\u00e1metro proporciona un recinto cuya \u00e1rea tome un valor deseado?<\/p>\n<p>Precisamos con un enunciado concreto:<\/p>\n<fieldset style=\"border: 1px solid #8A0808; padding: 10px;\">\n<p>Calculemos \\(a > 0 \\) para que el \u00e1rea del recinto acotado entre las par\u00e1bolas \\(y=x^2\\) e  \\(y=2a^2-x^2\\) sea \\(72 \\text{ u}^2\\).<\/p>\n<\/fieldset>\n<p><\/p>\n<p>\u00bfLo resolvemos juntos?<\/p>\n<p><div style=\"text-align: center;\">\n<iframe loading=\"lazy\" width=\"560\" height=\"315\" src=\"https:\/\/www.youtube.com\/embed\/r2eFHfVj5qY\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture\" allowfullscreen><\/iframe>\n<\/div>\n<p>\u00bfSab\u00edas hacerlo? \u00bfHas necesitado la ayuda del v\u00eddeo? Espero que, en cualquier caso, hayas disfrutado del problema. Gracias y hasta la pr\u00f3xima.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Hola. Una nueva entrada para el estudio del \u00e1rea del rencinto delimitado por dos curvas continuas. Pero hoy con una variaci\u00f3n: una [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"post-templates\/post_nosidebar.php","format":"standard","meta":{"footnotes":""},"categories":[19],"tags":[61,62,50],"class_list":["post-759","post","type-post","status-publish","format-standard","hentry","category-matematicas-ii","tag-calculo-integral","tag-integral-definida","tag-video"],"_links":{"self":[{"href":"https:\/\/www.pealfa.duckdns.org\/wordpress\/index.php?rest_route=\/wp\/v2\/posts\/759","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.pealfa.duckdns.org\/wordpress\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.pealfa.duckdns.org\/wordpress\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.pealfa.duckdns.org\/wordpress\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.pealfa.duckdns.org\/wordpress\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=759"}],"version-history":[{"count":1,"href":"https:\/\/www.pealfa.duckdns.org\/wordpress\/index.php?rest_route=\/wp\/v2\/posts\/759\/revisions"}],"predecessor-version":[{"id":760,"href":"https:\/\/www.pealfa.duckdns.org\/wordpress\/index.php?rest_route=\/wp\/v2\/posts\/759\/revisions\/760"}],"wp:attachment":[{"href":"https:\/\/www.pealfa.duckdns.org\/wordpress\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=759"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.pealfa.duckdns.org\/wordpress\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=759"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.pealfa.duckdns.org\/wordpress\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=759"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}